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Air gaps and the inductance factor

  • Compute the inductance factor of a gapped core from its dimensions, and the inductance from the turns.
  • Explain why a gap makes the inductance depend on the gap rather than on the core material.
  • Explain how a gap lowers the flux density that an inductor reaches at a given current.

A magnetic path behaves like a resistive circuit: the winding’s magnetomotive force, its turns times its current, drives the flux through reluctances in series, here the core’s and the gap’s [Erickson & Maksimović 2020, Ch. 10]. The core’s reluctance is its path length divided by its permeability and area; the gap’s is the gap length divided by the permeability of free space and the area. Because the core’s relative permeability is large, even a short gap can dominate the total.

The inductance per turn squared, the inductance factor ALA_L, is the inverse of the total reluctance [Dixon 2001], [Erickson & Maksimović 2020, Ch. 10]:

AL≈μ0Aelg+leμiA_L \approx \frac{\mu_0 A_e}{l_g + \frac{l_e}{\mu_i}}
ALA_L
inductance factor (per turn squared)
AeA_e
effective core area
lel_e
effective magnetic path length
lgl_g
air-gap length
μi\mu_i
initial relative permeability
μ0\mu_0
permeability of free space
Inductance factor of a gapped core✓ verified by 8 tests
Assumptions, convention and source
Assumptions
  • linear (unsaturated) magnetic material
  • no fringing flux at the gap
  • flux density uniform over A_e
Notes
fringing makes the real ALA_L larger than this estimate; use the manufacturer's ALA_L for a specified gap
Source
Dixon 2001; Erickson & Maksimović 2020, Ch. 10 (Basic Magnetics Theory: magnetic circuits)
Derivation
step-by-step sympy derivation
Equation id
mag.AL_gap · equations.yaml entry
L=ALN2L = A_L N^{2}
LL
inductance
ALA_L
inductance factor (per turn squared)
NN
number of turns
Inductance from the inductance factor✓ verified by 7 tests
Assumptions, convention and source
Assumptions
  • linear (unsaturated) magnetic material
Source
Dixon 2001; Erickson & Maksimović 2020, Ch. 10 (Basic Magnetics Theory)
Derivation
step-by-step sympy derivation
Equation id
mag.L_from_AL · equations.yaml entry

When the gap term dominates, ALA_L depends on the gap length and the area and hardly on μi\mu_i: the gap makes the inductance insensitive to the spread of the core material [Erickson & Maksimović 2020, Ch. 10].

The core material saturates at a given flux density, and a gap does not change that limit. It lowers the inductance factor, however, so a given inductance needs more turns, and at a given current the flux density falls (peak flux density): the gapped inductor carries more current before it saturates.

An example gapped core:

Gapped core example
SymbolValueHow it is obtained
AeA_e effective core area100 mm²given
lel_e effective magnetic path length50 mmgiven
lgl_g air-gap length0.5 mmgiven
μi\mu_i initial relative permeability2000given
NN number of turns20given
ALA_L inductance factor (per turn squared)239 nHInductance factor of a gapped core
LL inductance95.7 µHInductance from the inductance factor

With the given gap, the inductance factor is 239 nH, and 20 turns give 95.7 µH. The gap’s reluctance is much larger than the core’s here, so the result barely depends on μi\mu_i.

▶ Open in the equation explorer: Inductance factor of a gapped core
Preset from the example gapped-core

Sweep lgl_g on its logarithmic axis: for small gaps the core material sets ALA_L, for large gaps the gap does, and ALA_L then falls in inverse proportion to the gap length. Halve μi\mu_i at a small gap and at a large gap to see where the material still matters.

Measure the inductance of a winding on a pair of ungapped ferrite core halves. Then place thin non-magnetic spacers of known thickness, such as plastic film, between the halves and measure again. Compare the change with the equation, counting every place where the flux path crosses a spacer. The measured inductance is somewhat larger than predicted, because the flux fringes around the gap [Dixon 2001].

  • Fringing makes the real ALA_L larger. The flux bulges out around the gap, which widens its effective area, so the simple equation underestimates the inductance [Dixon 2001].
  • Use the manufacturer’s ALA_L for a specified gap. The manufacturer’s ALA_L is measured, while fringing is hard to calculate; the equation serves to understand a gap and to estimate a custom one.
  • Turns multiply as a square. Doubling the turns on the same core quadruples the inductance.
  • Book Magnetics Design Handbook (SLUP132) — L. H. Dixon, Texas Instruments (Unitrode) · retrieved 2026-09-23
    Lloyd Dixon's magnetics design handbook, reproduced by TI from the 2001 Unitrode edition. The ti.com copy requires a free myTI login.
  • Book chapter Basic Magnetics Theory (Ch. 10) — R. W. Erickson, D. Maksimović · retrieved 2026-09-23
    Magnetic circuits, the transformer model with magnetizing and leakage inductance, and core and winding loss mechanisms.
  • Course Magnetics for Power Electronic Converters — University of Colorado Boulder (Coursera) · retrieved 2026-09-23
    Magnetic circuits, core and winding losses, and inductor and transformer design.
  1. A core has AL=250 nHA_L = 250\,\mathrm{nH} per turn squared. How many turns give 100 μH100\,\mu\mathrm{H}?

    1. 4
    2. 20
    3. 40
    4. 400
    Answer and explanation

    Correct answer: B The turns squared are the inductance divided by ALA_L, 400; their square root is 20.

  2. The turns on a given core are doubled. What happens to the inductance?

    1. It doubles
    2. It quadruples
    3. It is unchanged
    4. It halves
    Answer and explanation

    Correct answer: B The inductance is ALA_L times the square of the turns.

  3. Why does a gap make the inductance nearly independent of the core material?

    1. The gap's reluctance dominates the total, and it depends only on the gap length and the area
    2. The gap raises the material's permeability
    3. The gap removes hysteresis
    4. The gap shortens the magnetic path
    Answer and explanation

    Correct answer: A With a large relative permeability, the core's reluctance is small compared with even a short gap's.

  4. Compared with the simple equation, how does fringing flux around a gap change the real ALA_L?

    1. It makes it smaller
    2. It makes it larger
    3. It has no effect
    4. It makes it depend on the current
    Answer and explanation

    Correct answer: B Fringing widens the gap's effective area, lowering its reluctance and raising ALA_L.

  5. A core has an effective area of 1 cm21\,\mathrm{cm^2} and a total gap of 1 mm1\,\mathrm{mm}; its own reluctance is negligible. What is ALA_L, ignoring fringing?

    1. 12.6 nH12.6\,\mathrm{nH}
    2. 126 nH126\,\mathrm{nH}
    3. 1.26 μH1.26\,\mu\mathrm{H}
    4. 12.6 μH12.6\,\mu\mathrm{H}
    Answer and explanation

    Correct answer: B μ0\mu_0 times the area divided by the gap: 4π×10−7×10−4/10−34\pi \times 10^{-7} \times 10^{-4}/10^{-3}.

  6. At the same inductance and current, how does a gapped core compare with an ungapped one of the same size?

    1. It reaches a lower flux density, because it needs more turns for the same inductance
    2. It reaches a higher flux density
    3. It saturates at a higher flux density because the gap raises the material's limit
    4. There is no difference
    Answer and explanation

    Correct answer: A The peak flux density is the inductance times the current divided by the turns and the area; the gap does not change the material's limit, but more turns lower the flux density.

The numbers in the examples, presets and exercises on this site are synthetic: round teaching values, not data from any real design.