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Transformers and coupled inductors

  • Apply the ideal-transformer relations with the site’s 1:n turns-ratio convention.
  • Add the magnetizing and leakage inductances to model a real transformer.
  • Tell a transformer, which passes energy through, from a coupled inductor, which stores it.

Two windings on one core, with perfect coupling, no magnetizing current and no loss, form an ideal transformer. With the turns ratio written 1:n, where nn is the number of secondary turns divided by the number of primary turns, the voltage is multiplied by nn and the current divided by nn [Alexander & Sadiku 2017, Ch. 13], [Erickson & Maksimović 2020, Ch. 6]:

V2=nV1V_2 = n V_1
V2V_2
secondary voltage
V1V_1
primary voltage
nn
turns ratio, secondary/primary
Ideal transformer: secondary voltage✓ verified by 7 tests
Assumptions, convention and source
Assumptions
  • ideal transformer: perfect coupling, no magnetizing current, no losses
Convention
turns ratio 1:n with nn the secondary turns divided by the primary turns (site convention)
Source
Alexander & Sadiku 2017, Ch. 13 (Magnetically Coupled Circuits); Erickson & Maksimović 2020, Ch. 6 (Converter Circuits)
Derivation
step-by-step sympy derivation
Equation id
xfmr.V2 · equations.yaml entry
I2=I1nI_2 = \frac{I_1}{n}
I2I_2
secondary current
I1I_1
primary current
nn
turns ratio, secondary/primary
Ideal transformer: secondary current✓ verified by 7 tests
Assumptions, convention and source
Assumptions
  • ideal transformer: perfect coupling, no magnetizing current, no losses
Convention
turns ratio 1:n; the secondary current is taken as flowing out of the secondary's dotted terminal
Notes
the power is conserved: the product of the secondary voltage and current equals that of the primary
Source
Alexander & Sadiku 2017, Ch. 13 (Magnetically Coupled Circuits); Erickson & Maksimović 2020, Ch. 6 (Converter Circuits)
Derivation
step-by-step sympy derivation
Equation id
xfmr.I2 · equations.yaml entry

The power is conserved, and an impedance connected to the secondary appears at the primary divided by n2n^2 [Alexander & Sadiku 2017, Ch. 13].

A real core has a finite permeability, so it takes a current to set up the flux, even with the secondary open. This magnetizing current is modelled by an inductance LML_M in parallel with the primary of an ideal transformer, referred to the primary [Erickson & Maksimović 2020, Ch. 6]. It grows while a voltage is applied to the winding, which is why a transformer must be reset in every period (see the forward converter).

Not all of the flux links both windings. The flux that links only one of them appears as a leakage inductance in series with that winding [Erickson & Maksimović 2020, Ch. 10]. It slows the transfer of current from one winding to the other, and in a flyback its energy must be absorbed at every turn-off (see the flyback page).

A transformer transfers energy from the primary to the secondary while both windings conduct, and ideally stores none. A flyback’s coupled inductor works differently: its magnetizing inductance stores energy while the primary conducts and releases it through the secondary afterwards [Erickson & Maksimović 2020, Ch. 6]. The two are therefore designed for different goals: the transformer for a small magnetizing current, the coupled inductor for a specified magnetizing inductance and stored energy [Erickson & Maksimović 2020, Ch. 10].

An example ideal transformer:

Ideal transformer example
SymbolValueHow it is obtained
nn turns ratio, secondary/primary0.25given
V1V_1 primary voltage48 Vgiven
I1I_1 primary current500 mAgiven
V2V_2 secondary voltage12 VIdeal transformer: secondary voltage
I2I_2 secondary current2 AIdeal transformer: secondary current

With a turns ratio of 0.25, the secondary has 12 V across it and carries 2 A: the voltage steps down by the same factor by which the current steps up.

▶ Open in the equation explorer: Ideal transformer: secondary voltage
Preset from the example transformer-ideal

Sweep nn over its logarithmic range: below one the transformer steps down, above one it steps up. Then compare with the flyback’s conversion ratio (flyback conversion ratio), in which the same factor multiplies the buck-boost ratio.

Drive the primary of a small signal transformer from a function generator with a sine wave within its rated frequency range, with the secondary open. Measure both winding voltages to find the turns ratio. Then measure the primary current with the secondary open, which is the magnetizing current, and with the secondary shorted, which is limited by the leakage inductance, and estimate both inductances from the voltage, current and frequency.

  • Check the turns-ratio convention. Data sheets and textbooks write turns ratios in different directions; this site always uses 1:n with nn the secondary turns divided by the primary turns.
  • The magnetizing current is not load current. It flows with no load at all, and the net volt-seconds on the winding must be zero in every period, or the magnetizing current grows until the core saturates [Erickson & Maksimović 2020, Ch. 6].
  • Mind the dots. Reversing one winding inverts the secondary voltage; in a flyback the winding polarity is chosen so that the diode blocks while the switch is on [Erickson & Maksimović 2020, Ch. 6].
  • Book chapter Basic Magnetics Theory (Ch. 10) — R. W. Erickson, D. Maksimović · retrieved 2026-09-23
    Magnetic circuits, the transformer model with magnetizing and leakage inductance, and core and winding loss mechanisms.
  • Book chapter Converter Circuits (Ch. 6) — R. W. Erickson, D. Maksimović · retrieved 2026-09-23
    How the basic topologies relate, and transformer-isolated versions including the flyback and forward converters.
  • Course Magnetics for Power Electronic Converters — University of Colorado Boulder (Coursera) · retrieved 2026-09-23
    Magnetic circuits, core and winding losses, and inductor and transformer design.
  1. An ideal transformer with turns ratio 1:n, n=0.2n = 0.2, has 50 V50\,\mathrm{V} across its primary. What is the secondary voltage?

    1. 2.5 V2.5\,\mathrm{V}
    2. 10 V10\,\mathrm{V}
    3. 50 V50\,\mathrm{V}
    4. 250 V250\,\mathrm{V}
    Answer and explanation

    Correct answer: B The secondary voltage is nn times the primary voltage.

  2. The secondary of the same transformer delivers 5 A5\,\mathrm{A}. What is the primary current?

    1. 0.2 A0.2\,\mathrm{A}
    2. 1 A1\,\mathrm{A}
    3. 5 A5\,\mathrm{A}
    4. 25 A25\,\mathrm{A}
    Answer and explanation

    Correct answer: B The secondary current is the primary current divided by nn, so the primary current is nn times 5 A5\,\mathrm{A}. The power is the same on both sides.

  3. A 10 Ω10\,\Omega resistor is connected to the secondary of an ideal transformer with n=0.5n = 0.5. What resistance does the primary see?

    1. 2.5 Ω2.5\,\Omega
    2. 5 Ω5\,\Omega
    3. 20 Ω20\,\Omega
    4. 40 Ω40\,\Omega
    Answer and explanation

    Correct answer: D An impedance on the secondary appears at the primary divided by n2n^2, here 0.250.25.

  4. What element models the current that a real transformer draws with its secondary open?

    1. The leakage inductance
    2. The magnetizing inductance
    3. The winding capacitance
    4. The load resistance
    Answer and explanation

    Correct answer: B Setting up the flux in a core of finite permeability takes a current, modelled by the magnetizing inductance in parallel with the primary.

  5. How does a flyback's coupled inductor differ from a forward converter's transformer?

    1. It has no secondary winding
    2. It stores energy in its magnetizing inductance and releases it later, instead of passing energy through while both windings conduct
    3. It needs no core
    4. It has no leakage inductance
    Answer and explanation

    Correct answer: B In the flyback the primary and the secondary conduct in turn; the energy waits in the magnetizing inductance in between.

  6. In the 1:n convention used on this site, what is nn?

    1. The primary turns divided by the secondary turns
    2. The secondary turns divided by the primary turns
    3. The total number of turns
    4. The ratio of the winding resistances
    Answer and explanation

    Correct answer: B The site follows Erickson's convention: 1:n with nn the secondary turns over the primary turns.

The numbers in the examples, presets and exercises on this site are synthetic: round teaching values, not data from any real design.